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How many moles are contained in 7.88 x 10^24 atoms of Iron
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How many moles are contained in 7.88 x 10^24 atoms of Iron

User Jantursky
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1 Answer

6 votes

Answer:

1.31 × 10^47

Step-by-step explanation:

1 mol of Fe =


1 \: mol \: of \ fe = 6.02 * 10 ^(23) \ \\ x \: mol \: offe \: = 7.88 * {10}^(24) \\ \\ \\ so \: 7.88 * {10}^(24) / 6.02 * {10}^(23) \\ \\ x = 1.31 * {10}^(47)

User Jpeskin
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