Register
How many moles are contained in 7.88 x 10^24 atoms of Iron
175k views
23 votes
How many moles are contained in 7.88 x 10^24 atoms of Iron

User Jantursky
by
8.9k points

1 Answer

6 votes

Answer:

1.31 × 10^47

Step-by-step explanation:

1 mol of Fe =


1 \: mol \: of \ fe = 6.02 * 10 ^(23) \ \\ x \: mol \: offe \: = 7.88 * {10}^(24) \\ \\ \\ so \: 7.88 * {10}^(24) / 6.02 * {10}^(23) \\ \\ x = 1.31 * {10}^(47)

User Jpeskin
by
8.9k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.3m questions

12.0m answers

Other Questions

Compare and contrast an electric generator and a battery??
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!