Question

What is the output of the following program? \#include using namespace std; int fun(int n ) \{ n++; return n; \} n++; // function call int main() int n=10

fun( n);
cout ≪n;
​ 12 10 Syntax error 11

Answer 1

The program defines a function that increments its parameter but doesn't affect the original value. Since the result of the function call isn't stored, the program outputs the original value of the variable, which is 10.

Step-by-step explanation:

The student is asking about the output of a C++ program snippet. The program defines a function called fun that takes an integer argument n, increments it by one, and then returns the new value. In the main function, we have an integer n initialized to 10, and then the fun function is called with n as an argument.

However, the result of the function call is not assigned to any variable, so the original value of n remains unchanged. Therefore, the output of the program will be 10, which is the original value of n in the main function.

The program defines a function called fun which takes an integer n as a parameter and increments it by 1. In the main function, an integer n is declared and initialized to 10.

Then the fun function is called with n as the argument. Although the fun function increments n by 1 and returns the incremented value, the returned value is not stored or assigned to any variable. Therefore, when n is printed in the main function, it still has the original value of 10. Hence, the output is 10.