Question

This is programming language C

Consider the following declaration of a string:
char foo[ ] = "To be\\\tor not\\\tto be."
This string contains three blank-space characters.
How many bytes of memory are allocated to store this value?
We assume each character requires one byte.

Answer 1

In C, the string char foo[] = "To be\\\tor not\\\tto be." allocates 23 bytes of memory, accounting for printable characters, special characters, and the null terminator.

Step-by-step explanation:

The declaration char foo[] = "To be\\\tor not\\\tto be." in the C programming language is for a string that includes characters for new line (\\) and tab (\t). To determine how many bytes are allocated, we need to count all characters, including these special characters, and the null terminator (\0) which is implicitly added at the end of the string. The string contains 18 printable characters, 2 new line characters, 2 tab characters, and 1 null terminator, totaling 23 bytes of memory allocated to store this value.

The given declaration of the string "To be or not to be" is: char foo[ ] = "To be\\\tor not\\\tto be."Since each character in C programming language requires one byte, we can count the number of characters in the string to determine the number of bytes allocated. In this case, the string contains 18 characters. Therefore, 18 bytes of memory are allocated to store this value.