Question

In. Problem 1 \# Modify and return the given dictionary as follows: if the key "a" H has a value, set the key "b" to have that value, and set the key "a" * to have the value \# \# prob_one ({ " a ": "candy", "b": "dint" })→{ "a": ";,"b∗:"candy

∗ } * prob_one ({ "a": "candy" })→{ " a ": "n, "b": "candy" } " prob_one(\{"a": "candy", "b": "carrot", "c": "meh" })→{ "a": ": "b": "candy", "c": "meh" def prob_one(dictionary): * Problem 1 code goes here: return dictionary

Answer 1

The problem requires modifying a dictionary by setting key 'b' to the value of key 'a', and then setting key 'a' to an empty string.

The solution is a simple function that checks for the existence of key 'a', copies its value to key 'b', and clears the value for key 'a'.

Step-by-step explanation:

The task is to modify a given dictionary in a specific way based on its current contents, particularly the values associated with certain keys. The problem is a straightforward coding exercise that involves checking the existence of a key and manipulating the values of the dictionary accordingly.

To achieve the desired functionality, you would write a function as such:

def prob_one(dictionary):
if 'a' in dictionary:
dictionary['b'] = dictionary['a']
dictionary['a'] = ''
return dictionary

This code checks if the key 'a' exists in the dictionary and if it does, it sets the key 'b' to have the same value as the key 'a', and then it sets the key 'a' to an empty string as per the given examples.