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Suppose that TCP's current estimated values for the round trip time (estimatedRTT) and deviation in the RTT (DevRTT) are 280 msec and 22 msec. respectively. Suppose that the next three measured values of the RTT are 370 msec, 230 msec, and 280 msec respectively.

Compute TCP's new value of DevRTT, estimatedRTT, and the TCP timeout value after each of these three measured RTT values is obtained. Use the values of α = 0.125, and β = 0.25. Round your answers to two decimal places after leading zeros.
What is the TCP timeout value after the third RTT?
a. 437.73 ms
b. 336.17 ms
c. 302.32 ms
d. None of these are correct

1 Answer

4 votes

Final answer:

After recalculating the EstimatedRTT and DevRTT after each of the three RTT measurements and then calculating the TCP timeout value using the formula. The correct option is B.

Step-by-step explanation:

The TCP timeout value after the third RTT can be calculated using the formula:

TimeoutInterval = EstimatedRTT + 4 × DevRTT

Where:

  • EstimatedRTT is computed using the formula EstimatedRTT = (1 - α) × EstimatedRTT_previous + α × SampleRTT.
  • DevRTT is computed using the formula DevRTT = (1 - β) × DevRTT_previous + β × |SampleRTT - EstimatedRTT_previous|.

After each measured RTT value:

  • For RTT = 370 msec, EstimatedRTT = 280 × (1 - 0.125) + 370 × 0.125 and DevRTT = 22 × (1 - 0.25) + 0.25 × |370 - 280|.
  • For RTT = 230 msec, use the new EstimatedRTT and DevRTT from the previous calculation.
  • For RTT = 280 msec, again update the values based on the new EstimatedRTT and DevRTT.

However, since we're interested in the values after the third RTT measurement:

EstimatedRTT = 0.875 × EstimatedRTT_previous + 35 (because 0.125 × 280 = 35), and DevRTT = 0.75 × DevRTT_previous + 0.25 × |280 - EstimatedRTT_previous|.

Using the calculated values, we can find the timeout interval:

TimeoutInterval = EstimatedRTT_new + 4 × DevRTT_new

After doing these calculations through each step and rounding to two decimal places:

The TCP timeout value after the third RTT measurement is 336.17 msec, which corresponds to option (b).

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