Final answer:
The output of the function calls in part (a) and (b) are 3 and 3, respectively.
Step-by-step explanation:
In part (a), the function call test1(3) will return the square root of the sum of 3 squared plus 0 squared, which is 3.
In part (b), the function call test2(3) will return the value 3 because the nargin parameter is equal to 2, so the function calculates the square root of the sum of 3 squared plus 0 squared.