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A Z-channel has a bit-flip parameter of p = 0.2. If the random variable X is input and the random variable Y is output, plot the mutual information I (X; Y) as a function of α where P (X = 0) = α. Identify the value of α that maximizes the mutual information.

User Gbrener
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Final answer:

The mutual information I(X;Y) between random variables X and Y quantifies the amount of information that X contains about Y. In this case, we have to calculate the entropies of X and X given Y for a Z-channel with a bit-flip parameter of p=0.2. The value of alpha that maximizes the mutual information can be found by taking the derivative of the difference between entropies with respect to alpha and solving for alpha.

Step-by-step explanation:

In information theory, the mutual information between random variables X and Y, denoted as I(X;Y), quantifies the amount of information that X contains about Y. It is defined as the difference between the entropy of X and the entropy of X given Y:

I(X;Y) = H(X) - H(X|Y)

In this case, the random variable X represents the input and the random variable Y represents the output of a Z-channel with a bit-flip parameter of p = 0.2. To find the mutual information I(X;Y) as a function of alpha, where P(X=0) = alpha, we need to calculate the entropies of X and X given Y.

Let's say P(Y=0) = q. Since Y is the output of the Z-channel, the probability of correct transmission is given by P(correct) = (1-p)(1-q) + pq = (1-0.2)(1-q) + 0.2q = 0.8 - 0.6q + 0.2q = 0.8 - 0.4q. Therefore, P(Y=1) = 1 - P(correct) = 0.4q.

The entropy of X is given by H(X) = -P(X=0)log2(P(X=0)) - P(X=1)log2(P(X=1)) = -alpha*log2(alpha) - (1-alpha)*log2(1-alpha).

The conditional entropy of X given Y is given by H(X|Y) = -P(X=0,Y=0)log2(P(X=0,Y=0)) - P(X=1,Y=0)log2(P(X=1,Y=0)) - P(X=0,Y=1)log2(P(X=0,Y=1)) - P(X=1,Y=1)log2(P(X=1,Y=1)).

Since Y and Z are independent, we have P(X=0,Y=0) = P(X=0)P(Y=0) = alpha*q and P(X=1,Y=0) = P(X=1)P(Y=0) = (1-alpha)*q.

The value of alpha that maximizes the mutual information I(X;Y) is the one that maximizes the difference H(X) - H(X|Y). To find this maximum, we can take the derivative of the difference with respect to alpha, set it equal to zero, and solve for alpha. However, this involves a lot of algebraic manipulation, and it's easier to use numerical methods or calculus software to find the maximum.

User Jiyoung
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