Final answer:
To create 6 subnetworks with the first subnet supporting at least 58 hosts, a /26 subnet mask is needed, which allows for 62 usable host addresses per subnet. The first subnet is 192.168.1.0/26.
Step-by-step explanation:
To subnet the address 192.168.1.0/24 into 6 subnetworks with the first subnet having at least 58 hosts, you need to determine the appropriate subnet mask that will accommodate the host requirement while allowing for the creation of the necessary number of subnets.
First, let's calculate the subnet mask that allows for at least 58 hosts in a subnet. To support 58 hosts, you need enough host bits to represent at least 58 different values. Since 26 = 64 (which would allow for 62 usable host addresses as we must subtract 2 for the network and broadcast addresses), you need 6 host bits. Therefore, you will use a subnet mask of /26, which leaves you 26 bits for network and 6 bits for host addresses (32 - 6 = 26).
The subnet mask /26 gives us the subnet address increment of 26 = 64. Hence, the subnets will be:
- 192.168.1.0/26 - First subnet (64 addresses, 62 usable)
- 192.168.1.64/26
- 192.168.1.128/26
- 192.168.1.192/26
- and so on, up to the sixth subnet.