Question

A 12 kg chair initially at rest on a horizontal floor requires a 112 N horizontal force to set it in motion.

Calculate the coefficient of static friction.

Round your answer to two decimal places (the hundredth place). You do not need to include units.

Answer 1

Step-by-step explanation:

0.98

The coefficient of static friction is calculated by dividing the force required to set the chair in motion (112 N) by the weight of the chair (12 kg). This gives us 112/12 = 9.3. The coefficient of static friction is equal to the ratio of the force required to set the chair in motion to the weight of the chair, so 9.3/9.8 = 0.98.