Final answer:
To find the maximum/minimum value of the quadratic function represented by h(t) = 40t - 16t², we need to determine the vertex of the parabola. The vertex is found using the equation x = -b/2a, where x is the x-coordinate of the vertex and a and b are the coefficients. In this case, the maximum/minimum value of h(t) is 25.
Step-by-step explanation:
The expression h(t) = 40t - 16t² represents a quadratic function. To find the maximum/minimum value, we need to determine the vertex of the parabola. The vertex of a parabola of the form y = ax² + bx + c is given by the equation x = -b/2a. In this case, x = -40/(2*(-16)) = 1.25. Substituting this value back into the equation, we find h(1.25) = 40(1.25) - 16(1.25)² = 25.