Final answer:
The given sequence of ARM instructions perform various operations on arrays A and B, resulting in array A containing {6, 4, 3, 4}.
Step-by-step explanation:
The given sequence of ARM instructions perform various operations on the arrays A and B. Let's break down the instructions one by one:
- LDR RO, =A: This loads the address of array A into register RO.
- LDR R1, -B: This loads the address of array B into register R1, with a negative offset of -B.
- MOV R2, #0: This moves the value 0 into register R2.
- LDR R3, [RO, R2]: This loads the first element of array A into register R3.
- LDR R4, [R1, R2]: This loads the first element of array B into register R4.
- ADD R3, R4: This adds the values in R3 and R4 together.
- STR R3, [RO, R2]: This stores the sum back into the first element of array A.
- ADD R2, #8: This increments R2 by 8 to move to the next element.
- LDR R3, [RO, R2]: This loads the next element of array A into R3.
- LDR R4, [R1, R2]: This loads the next element of array B into R4.
- SUB R4, R3: This subtracts R3 from R4.
- STR R4, [RO, R2]: This stores the difference back into the next element of array A.
After executing all the instructions, the values in array A would be {6, 4, 3, 4}.