Question

Given 3 digit numbers that can be formed using the digits from 1 to 9.

Required number of 3-digit numbers= arranging 3 digits with the total number of 9 digits.
= ⁹P₃ = (9 × 8 × 7) = 504.
Hence, the required number of numbers = 504.

Answer 1

The student is asking how many 3-digit numbers can be formed using the digits 1 to 9. The answer is 504.

Step-by-step explanation:

The student is asking how many 3-digit numbers can be formed using the digits 1 to 9. To calculate this, we can use the formula for permutations. The formula for permutations is nPr, where n is the total number of digits and r is the number of digits in each number. In this case, n = 9 and r = 3, so the formula becomes 9P3.

Using the formula, we can calculate 9P3 as (9 x 8 x 7) = 504. Therefore, there are 504 different 3-digit numbers that can be formed using the digits 1 to 9.