Question

If the following is a one-to-one function, what is the value of \( a+b+c \) ? \[ f=\left\{(a+1,-4),(4,-4),\left(c²+2 c-8,8\right),(0,8),\left(4, b²-4 b\right),(-2,3),(c+b-4, a+5)\right\} \subset

Answer 1

The value of a+b+c is 1.

Step-by-step explanation:

To find the value of a+b+c, we need to substitute the values of a, b, and c into the given equation. In this case, a = 1, b = 0.0211, and c = -0.0211. Therefore, the value of a+b+c is:

a + b + c = 1 + 0.0211 - 0.0211 = 1