Question

Create an interface named Comparable Area that contains one method named compareToArea(). This method should return 0 when the object has the same area as another object, -I should be returned when the object has an area less than another object, and I returned otherwise.

Modify the Rectangle class to implement the ComparableArea interface as well as the Comparable interface implemented in the previous review. Modify the existing client code to test the new method.

Answer 1

The Comparable Area interface, including the compareToArea() method, allows classes to compare areas. A ratio can compare two areas, and proportions can be used to find similarities and differences between various distances or areas.

Step-by-step explanation:

Implementing ComparableArea Interface in Rectangle Class

To create the Comparable Area interface with the compareToArea() method, we define it so that it allows a class to compare its area with another object's area. In the provided scenario, the method should return 0 if areas are equal, -1 if the object's area is smaller, and 1 if the object's area is larger. We then modify the Rectangle class to implement this interface alongside the existing Comparable interface. To test the new method, the client code will have to be updated to call compareToArea() and check the result.

When comparing two areas, you can write a ratio to see how they relate to each other. For example, if you have two squares with different side lengths, you can compare their areas by squaring the side lengths of each and then forming a ratio. Similarly, in a set of areas, such as A₁, A₂, and A3, you would compare sizes to determine an order like A₁ > A₂ = A3 based on computation of their respective areas.

Using a scale to find the area of a space involves measuring the length and width and performing the necessary calculations for area. If you have different distances or areas to compare, using proportions can help identify differences and similarities between them.