Question

Modify the Disk class to implement the Comparable interface. Two disks are equal when they have the same thickness and same radius. Modify the existing client code to test the new method.

Answer 1

To implement the Comparable interface in the Disk class, define the compareTo() method to compare disks based on thickness and radius. Modify the client code to create two Disk objects and use the compareTo() method to compare them.

Step-by-step explanation:

In order to implement the Comparable interface, the Disk class needs to define the compareTo() method. This method should compare two disks based on their thickness and radius.

For example, the compareTo() method could compare the thickness of the two disks first. If the thicknesses are equal, then the method could compare the radii of the disks. If both the thicknesses and radii are equal, the method should return 0 to indicate that the disks are equal.

To modify the existing client code to test the new method, you can create two Disk objects and use the compareTo() method to compare them. For example:

Disk disk1 = new Disk(1.5, 0.5); // the first disk
Disk disk2 = new Disk(1.5, 0.5); // the second disk
disk1.compareTo(disk2); // compare the two disks