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Rex and Tex board the bumper cars at the local carnival. Rex is moving at full speed of 2.05 m/s when he rear-ends Tex who is at rest in his path. Tex and his 125kg car lunge forward at 1.40m/s. Determine the post-collision speed of Rex and his 125kg car.

User Morphles
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Final answer:

Rex and Tex board the bumper cars at the local carnival. Rex is moving at full speed of 2.05 m/s when he rear-ends Tex who is at rest in his path. Tex and his 125kg car lunge forward at 1.40m/s. The post-collision speed of Rex and his 125kg car is 1.025 m/s.

Step-by-step explanation:

Given the mass of Rex's car (125kg) and his initial velocity (2.05 m/s), we can calculate his initial momentum using the formula:

Initial momentum (Pi) = Mass (m) * Velocity (v)

Pi = 125 kg * 2.05 m/s = 256.25 kg*m/s

After the collision, both Rex and Tex's car move together at a final velocity.

To calculate this final velocity, we use the conservation of momentum:

Initial momentum (Pi) = Final momentum (Pf)

256.25 kg*m/s = (Mass of Rex's car + Mass of Tex's car) * Final velocity

Final velocity = 256.25 kg*m/s / (125 kg + 125 kg)

= 1.025 m/s

Therefore, the post-collision speed of Rex and his 125kg car is 1.025 m/s.

User Cmdematos
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