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3 votes
Return the ingredient breakdown from the details amount, measure, and ingredient.

The starter code is:
def parse ingredient(raw ingredient detail: str) ->
tuple[float, str, str] :
An example of how the function is to run:
>>> parse_ingredient('0.5 tsp coffee granules')
(0.5, 'tsp', 'coffee granules')
>>> parse_ingredient('1 large banana')
(1.0, 'large', 'banana')

1 Answer

5 votes

The question asks for a Python function to parse an ingredient detail into a structured tuple. The function 'parse_ingredient' must identify and return the amount as a float, the measurement unit, and the ingredient name. String handling techniques like 'split()' can be used to achieve this.

The student's question pertains to writing a Python function that parses a string representing a raw ingredient detail and returns a tuple containing the amount, measurement unit, and the ingredient name. As per the specifications, the parse_ingredient function should split and interpret the raw ingredient string and cast the amount as a float to ensure numerical values are handled correctly.

An example implementation would involve using string handling methods such as split() to divide the raw ingredient string into its constituent parts. The first part is typically the amount, which can be converted to a float, followed by the measurement and the name of the ingredient itself.

So, the function parse_ingredient facilitates the breakdown of dietary details into a structured and standardized format, which can be key for recipe management and nutritional analysis.

User Rico Suter
by
8.3k points