Question

H(t)=-4t²+48t+3 solve for height 3 seconds after the launch

Answer 1

To find the height 3 seconds after launch using the function h(t) = -4t² + 48t + 3, substitute t with 3 and solve the equation to get a height of 111 meters.

Step-by-step explanation:

To solve for the height 3 seconds after the launch, using the given height-time function h(t) = -4t² + 48t + 3, simply substitute t = 3 into the equation:

h(3) = -4(3)² + 48(3) + 3

Calculate the square of 3:

h(3) = -4(9) + 48(3) + 3

Multiply this out:

h(3) = -36 + 144 + 3

Add the values:

h(3) = 111 meters

Therefore, the height of the projectile 3 seconds after launch is 111 meters.