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Given the IEEE-754 Single Precision Floating Point number (stored Excess-127) 101111000101011000000000000000002, determine the following:

a. The sign of the mantissa
b.The magnitude of the exponent (convert to base 10)
c.The sign of the exponent

User Danielius
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Final answer:

The sign of the mantissa is negative, the magnitude of the exponent is 9461120 in base 10, and the sign of the exponent is positive.

Step-by-step explanation:

The given IEEE-754 Single Precision Floating Point number is 101111000101011000000000000000002. To determine the sign of the mantissa, we look at the leftmost bit. In this case, it is a 1, which indicates a negative mantissa. The magnitude of the exponent can be found by converting the remaining bits (01111000101011000000000000000000) to base 10. This is equal to 9461120. Finally, the sign of the exponent is determined by looking at the next leftmost bit, which is 0. This indicates a positive exponent.

User RStyle
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