Final answer:
The storage size for a 100×100 DICOM image, based on 16 bits per pixel and not including metadata, is approximately 20,000 bytes or 19.53 KB. None of the provided options (A, B, C, D) are correct, as they greatly exceed the calculated storage size.
Step-by-step explanation:
To determine the storage size needed for a DICOM image that is 100×100 pixels, we need to consider factors such as bit depth and whether the image is compressed or uncompressed. DICOM images are typically stored with a bit depth of 16 bits per pixel, meaning each pixel requires 16 bits (or 2 bytes) of storage. Therefore, for a 100×100 DICOM image:
- Calculate the total number of pixels: 100×100 = 10,000 pixels.
- Calculate the total number of bytes: 10,000 pixels × 2 bytes/pixel = 20,000 bytes.
- Since there are 1,024 bytes in a kilobyte, we divide the total number of bytes by 1,024 to get the size in kilobytes (KB): 20,000 bytes / 1,024 = 19.53 KB.
However, the actual size needed to store a DICOM image will typically be larger because the DICOM file format also includes metadata about the image. Nevertheless, the options given are significantly larger than the calculated size, indicating that the question may contain a misunderstanding or a typo.
In conclusion, none of the given options (A.256,000,000, B.128,000,000, C.160,000, D.8,000) accurately reflect the storage size needed for a 100×100 DICOM image when calculated only based on pixel data. The closest approximate size in bytes is 20,000 bytes, and after conversion into kilobytes, it is approximately 19.53 KB which is much smaller than any of the options provided.