Final answer:
To write a program in MIPS that takes an integer input from the user and multiplies it by 8 using shift operations, you can use the provided code. The program prompts the user to enter an integer, stores it in $t5, multiplies it by 8 using shift operations, and then prints the value of bits 6 to 10 of $t5. The code includes detailed comments to explain each step.
Step-by-step explanation:
To write a program in MIPS that takes an integer input from the user and multiplies it by 8 using shift operations, you can use the following code:
.data
prompt: .asciiz "Enter an integer: "
result_prompt: .asciiz "The number you entered:"
after_multiply_prompt: .asciiz "After it is multiplied by 8:"
bits_prompt: .asciiz "The bits [6-10] are:"
.text
.globl main
main:
# Prompt the user to enter an integer
li $v0, 4
la $a0, prompt
syscall
# Read the integer input from the user
li $v0, 5
syscall
# Store the input integer in $t5
move $t5, $v0
multiply:
# Multiply the number by 8 using shift operations
sll $t5, $t5, 3
# Print the entered number in decimal value
li $v0, 4
la $a0, result_prompt
syscall
li $v0, 1
move $a0, $t5
syscall
# Print the number after being multiplied by 8
li $v0, 4
la $a0, after_multiply_prompt
syscall
li $v0, 1
move $a0, $t5
syscall
# Print the value of bits 6 to 10 of $t5
li $v0, 4
la $a0, bits_prompt
syscall
li $v0, 1
move $a0, $t5
srl $a0, $a0, 6
andi $a0, $a0, 0b0000000000000000000011111
syscall
# Check if the entered number is 0
beqz $t5, exit
# Otherwise, repeat the process
j multiply
exit:
# Exit the program
li $v0, 10
syscall