Question

Calculate the change in chemical potential of 1 mole of glucose molecules transferred down a 1000x fold (from high to low concentration) glucose concentration gradient at 300K.

a) Δμ = RT ln(1000).
b) Δμ = -RT ln(1000).
c) Δμ = 1000 / RT.
d) Δμ = RT / 1000.

Answer 1

The change in chemical potential of 1 mole of glucose molecules transferred down a 1000x concentration gradient at 300K is Δμ = -RT ln(1000).

Step-by-step explanation:

The change in chemical potential of 1 mole of glucose molecules transferred down a 1000x fold glucose concentration gradient at 300K can be calculated using the formula Δμ = -RT ln(C2/C1). Since the glucose is moving down its concentration gradient from a higher to a lower concentration, the change in chemical potential will be negative. At temperature 300K, using the gas constant R (8.3145 J/mol K), the calculation will be Δμ = - (8.3145 J/mol K) * (300 K) * ln(1000).

The correct answer is: b) Δμ = -RT ln(1000).