Question

How much energy is consumed if 4.909g of water is evaporated?

a) 40 kJ
b) 4.18 kJ
c) 2260 kJ
d) None of the above

Answer 1

The energy required to evaporate 4.909g of water is calculated using the latent heat of vaporization (2256 kJ/kg). After converting the mass to kilograms, the energy consumed is found to be approximately 11.08 kJ, indicating that the correct answer is 'None of the above'.

Step-by-step explanation:

To calculate the energy consumed during the evaporation of water, we must use the latent heat of vaporization, which is the heat required to convert liquid water into water vapor without changing its temperature. The latent heat of vaporization of water is 2256 kJ/kg. Given that we have 4.909g of water, we must convert this mass to kilograms to use in our calculation:

4.909 g = 0.004909 kg

Now we can calculate the energy (Qv) required for vaporization:

Qv = m * Lv = 0.004909 kg * 2256 kJ/kg = 11.078224 kJ

Therefore, none of the provided options (a, b, or c) are correct. The correct amount of energy consumed to evaporate 4.909g of water is approximately 11.08 kJ.