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Why is dS > 0 during the folding process then?

a) Increase in energy
b) Decrease in energy
c) Increase in disorder
d) Decrease in disorder

1 Answer

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Final answer:

The correct answer is c) Increase in disorder. During a folding process such as protein folding, the entropy of the protein molecule decreases due to the more ordered structure, but the overall entropy of the system increases due to increased disorder in the surroundings.

Step-by-step explanation:

The question pertains to the concept of entropy, which is a measure of disorder or randomness in a system. When discussing why dS > 0 during the folding process, it refers to the change in entropy (S) which must be greater than zero if the disorder is increasing. The answer to the question is c) Increase in disorder. Folding in this context, likely refers to the process by which proteins fold into their functional shapes.

This process is typically associated with a decrease in entropy of the protein molecule itself as it adopts a more ordered structure. However the overall entropy of the system, including the surrounding environment increases due to the release of water molecules that were previously structured around the unfolded protein.

There are multiple points to understand regarding entropy and its changes during physical processes:

  • Melting ice into water increases entropy because the highly ordered solid structure is converted into a more disorderly liquid state.
  • Energy transfer from a concentrated state to a dispersed state generally increases entropy because it spreads energy out over more particles or space, increasing disorder.
  • The disordered condition is one of high entropy and is more likely than a highly ordered condition due to the tendency for systems to naturally progress towards maximum disorder.
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