Final answer:
Calling push(x) on a pointer s that points to a stack results in the value 'x' being added to the top of the stack. This operation increases the number of elements in the stack by 1, not the stack size by 'x'.
Step-by-step explanation:
When content loaded s is a pointer to a stack, and you call push(x) on s, you are performing an action specific to data structures in the field of computer science. The 'push' operation is one of the fundamental methods that can be performed on a stack. This operation involves adding an element to the collection, and in this context, the correct answer to what happens when you call push(x) on s is that it adds x to the top of the stack. This action essentially increases the count of items in the stack by 1, but it does not increase the size by 'x' units as that would imply increasing the stack's capacity rather than its current count of elements.
In summary, when you call push(x) on a stack pointer s, you are placing the value 'x' on the top of the stack, thereby increasing the stack's element count. It is important to note that adding an element to the stack does not alter the size of each element already on the stack or the value of 'x' itself.