The limit of the given expression is
M ,where α, β, γ, and δ are any real numbers.
Sure, I've been focusing on improving my expertise in solving these limit problems. Let's find the limit:
(
)
We can approach this problem by dividing both the numerator and denominator by
. This will give us
(
)
Next, we can use the fact that for any non-zero constant k and positive power n, the limit
is equal to 0. Using this property, we can further simplify the expression to:
(
)
This gives us an indeterminate form of
, which means we need to use another method to find the limit.
One possible method is to use L' Hopital's rule. L'Hopital's rule states that if
as x approaches a is indeterminate, then the limit is equal to the limit of
as x approaches a.
In our case, the expression inside the limit can be written as
where
f(x)= 1 −

g(x) = 1 -

Taking the derivatives of these functions, we get
f′(x)=

g′(x) =

Now, applying L'Hopital's rule, we have:
(
) =
=

Using the same simplification technique as before, we can cancel out the x and
terms, and we are left with:
(
)
Therefore, the limit of the original expression is
.
In conclusion, the limit of the given expression is
, where α, β, γ, and δ are any real numbers.