Final answer:
The coding strand complementary to the template 3'-TACAAG-5' is 5'-ATGTTA-3'. The transcribed mRNA sequence is 5'-AUGUUU-3', which translates into a polypeptide chain starting with methionine followed by phenylalanine.
Step-by-step explanation:
If the template strand of DNA is 3'-TACAAG-5', we can infer the sequence of the coding strand and the mRNA molecule produced during transcription, as well as predict the polypeptide chain that will result from translation.
The coding strand of DNA is complementary to the template strand but runs in the opposite direction; thus, for the given template, the coding DNA sequence is 5'-ATGTTA-3'. DNA base pairing rules indicate that adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G). The mRNA molecule, however, is generated from the template DNA using uracil (U) instead of thymine (T) in RNA. Therefore, the mRNA sequence transcribed from the given template strand will be 5'-AUGUUU-3'.
During translation, this mRNA sequence is read as codons by the ribosome to synthesize the corresponding polypeptide chain. Each codon corresponds to a specific amino acid or a stop signal. For the mRNA sequence 5'-AUGUUU-3', the amino acids are methionine (AUG) and phenylalanine (UUU). Thus, the polypeptide chain will start with methionine and followed by phenylalanine.