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The tens digit is 4 more than twice the ones digit. The sum of the digits is 4. How many candy canes are in

the jar? Find the tens digit (x) and the ones digit (y).
Ordered Pair O:

2 Answers

3 votes

Answer: To solve this problem, we can use the given information to set up a system of equations. Let's use x to represent the tens digit and y to represent the ones digit.

From the given information, we have the following equations:

x = 2y + 4 (The tens digit is 4 more than twice the ones digit.)

x + y = 4 (The sum of the digits is 4.)

We can solve this system of equations to find the values of x and y.

Using equation 1, we can substitute the expression for x from equation 1 into equation 2: (2y + 4) + y = 4 3y + 4 = 4 3y = 4 - 4 3y = 0 y = 0

Now that we have found the value of y, we can substitute it back into equation 1 to find the value of x: x = 2(0) + 4 x = 4

So, the ordered pair (x, y) is (4, 0).

As for the number of candy canes in the jar, it seems like there might be a mistake in the problem statement. The number of candy canes in the jar is not directly related to the digits of a number. If you have any other information related to the number of candy canes, please provide it and I can help you further.

User Phifa
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7.1k points
5 votes
4,0 is your answer just toke The test
User Deonna
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7.9k points