87.6k views
4 votes
A car of mass 810 kg drives around a circular track at a speed of 15 m/s. If the radius of the track is 150 m, what is the average centripetal force exerted on the car?

1 Answer

1 vote

Final answer:

A car of mass 810 kg drives around a circular track at a speed of 15 m/s. If the radius of the track is 150 m, the average centripetal force exerted on the car is 1215 N.

Step-by-step explanation:

The centripetal force exerted on an object moving in a circular path is given by the formula:

Fc = (m*v2)/r

Where:
- Fc is the centripetal force
- m is the mass of the object
- v is the speed of the object
- r is the radius of the circular path

Using the given values:
- m = 810 kg
- v = 15 m/s
- r = 150 m

Substituting the values into the formula, we have:
Fc = (810 kg * (15 m/s)2) / 150 m

Simplifying the expression, we get:
Fc = 1215 N

Therefore, the average centripetal force exerted on the car is 1215 N.

User Tushar Asodariya
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.