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38 votes
Find the slope of the line through (7,-6),perpendicular to y=4x+2

User Daniel Zhang
by
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1 Answer

25 votes
25 votes

Answer:

4y+x+17=0

Explanation:

y=4x+2

For a point to be perpendicular to a line

then the product of the two gradients must be negative one (I.e, m1×m2=-1)

where m1= 4

m2=-(1/m1)

m2=-1/4

point (7,-6)

x1=7 y1=-6

from the general equation of a line

y-y1=m(x-x1)

y-(-6)=-1/4(x-7)

y+6=-1/4(x-7)

y+6=-1/4x+7/4

y+1/4x=(7/4)-6

y+1/4x=-17/4

y+1/4x+17/4=0

4y+x+17=0

User LostInComputer
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