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A one liter solution of 0.7 M KCl (74 g/mol) is evaporated and 10 g of KCl are recovered. Which is the percent recovery of KCl?

User Amnn
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Final answer:

The percent recovery of KCl can be calculated by dividing the mass of KCl recovered by the initial mass of KCl and then multiplying by 100. In this case, the percent recovery is 19.3%

Step-by-step explanation:

The percent recovery of KCl can be calculated by dividing the mass of KCl recovered by the initial mass of KCl and then multiplying by 100. In this case, the initial mass of KCl is determined by multiplying the molarity (0.7 M) by the molar mass (74 g/mol) and the volume (1 L). This gives an initial mass of 51.8 g. The percent recovery is then calculated by dividing the recovered mass (10 g) by the initial mass (51.8 g) and multiplying by 100:

Percent recovery = (10 g / 51.8 g) * 100 = 19.3%

User Jeff Mitchell
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