Final answer:
For a composite number m > 4, the factorial (m-1)! will contain m as a factor, making (m-1)! congruent to 0 modulo m.
Step-by-step explanation:
The question asks about the congruence of the factorial of a composite number m minus one, denoted as (m-1)!, modulo m. For a composite number m > 4, one or more factors of (m-1)! will be the factors of m itself. This means that the product (m-1)! will contain m as a factor, hence (m-1)! ≃ 0 (mod m). So the correct answer is (b) (m-1)! ≃ 0 (mod m).