Final answer:
The given loop in the C program will run until scanf encounters an error or EOF. The loop's operation depends on the return value of scanf which reads input into variable i and terminates when it can no longer successfully read input.
Step-by-step explanation:
The code snippet provided is a C program loop that will execute based on the return value of the scanf function. The scanf function is used for input in C programming, and it returns the number of items successfully read. In this case, because there are typos in the code snippet, we must assume that it was meant to read a string into a variable i and then print the value of i using printf.
The loop can either run until scanf encounters an error or EOF (End of File) is reached, or if the incorrect type of input is provided for the expected data type. Assuming that i is a character array and the missing quotation marks for the format string are fixed, the correct syntax of scanf would be scanf("%s", i), and printf would be printf("%s", i). In this corrected form, the loop will continue to run as long as scanf successfully reads a string into i. If an error or EOF occurs while scanf is executed, the loop will terminate.
Therefore, the correct answer is: a) Until scanf encounters an error or EOF.