Final answer:
The expression of the lacZ+ and lacY+ genes in the transformed merodiploid bacterium is constitutive due to the presence of a super-repressor encoded by the lacIs allele on the F' plasmid.
Step-by-step explanation:
The expression of the genes lacZ+ and lacY+ in the merodiploid bacterium with the genotype lacI+ o+ lacZ+ lacY that was transformed with an F' plasmid carrying lacIs o+ lacZ lacY+ is constitutive. This is because the lacIs allele codes for a super-repressor that cannot be inactivated by allolactose, meaning the repressor will continually block the transcription of the lac operon even in the presence of the inducer lactose. Therefore, the lacZ+ and lacY+ genes on the F' plasmid will be expressed constitutively, as their regulation by the super-repressor is not influenced by the presence of lactose.