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A 1,500 kg car accelerates uniformly from rest to 10.0 m/s in 3.00 s. What is the power delivered by the engine in this time interval?

User Mirko
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Final answer:

The power delivered by the engine in the given time interval is 16,650 watts (or 16.65 kilowatts).

Step-by-step explanation:

To calculate the power delivered by the engine, we can use the formula:

Power = (Force x Distance) / Time

First, we need to calculate the force. Using Newton's second law of motion:

Force = Mass x Acceleration

Given that the car has a mass of 1,500 kg and accelerates uniformly from rest to 10.0 m/s in 3.00 s, we can calculate the force.

Acceleration = Change in Velocity / Time

= (10.0 m/s - 0 m/s) / 3.00 s

= 3.33 m/s²

Force = 1,500 kg x 3.33 m/s²

= 4,995 N

Next, we can substitute the force value into the power formula.

Power = (4,995 N x 10.0 m) / 3.00 s

= 16,650 W

Therefore, the power delivered by the engine in this time interval is 16,650 watts (or 16.65 kilowatts).

User Szydlovski
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