Question

The density of ethanol is 1.09g/cm³, and the density of propylene is 0.97g/cm³. 80 liters of ethanol are mixed with 148 liters of propylene to make 228 liters of antifreeze. Work out the density of the antifreeze in g/cm³.

a) 1.01 g/cm³
b) 1.05 g/cm³
c) 1.10 g/cm³
d) 1.15 g/cm³

Answer 1

The density of the antifreeze is 1.01 g/cm³.

Step-by-step explanation:

To calculate the density of the antifreeze, we need to first calculate the total mass of the mixture and then divide by the total volume.

The mass of 80 liters of ethanol can be calculated using its density: 80 liters * 1.09 g/cm³ = 87.2 g

The mass of 148 liters of propylene can be calculated using its density: 148 liters * 0.97 g/cm³ = 143.56 g

The total mass of the mixture is 87.2 g + 143.56 g = 230.76 g

The volume of the antifreeze is given as 228 liters.

Now, we can calculate the density: Density = Mass / Volume = 230.76 g / 228 liters = 1.01 g/cm³

Therefore, the density of the antifreeze is approximately 1.01 g/cm³.