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CaF₂ solid has Ksp = 3.9 x 10⁻¹¹, PbCl₂ solid has Ksp = 1.7 x 10⁻⁵, which one has a larger solubility in water?

a) CaF₂
b) PbCl₂
c) Both have the same solubility
d) Insufficient information to determine

1 Answer

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Final answer:

PbCl₂ has a larger solubility in water than CaF₂.

Step-by-step explanation:

In order to determine which compound has a larger solubility in water, we need to compare their solubility product constants (Ksp). The Ksp values for CaF₂ and PbCl₂ are 3.9 x 10⁻¹¹ and 1.7 x 10⁻⁵, respectively. The compound with the larger Ksp value will have a greater solubility in water. Therefore, PbCl₂ has a larger solubility in water than CaF₂.

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