Final answer:
It would take approximately 2790 seconds to go from 40 mph to 9 mph in 519 ft.
Step-by-step explanation:
To calculate the time it takes for a car to go from 40 mph to 9 mph in 519 ft, we can use the equations of motion. First, we need to find the acceleration of the car using the formula:
a = (vf - vi) / t
where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time taken. Solving for t, we get:
t = (vf - vi) / a
Plugging in the values, we have:
t = (9 mph - 40 mph) / (40 mph - 0 mph) = -31 mph / -40 mph = 0.775 hours = 0.775 * 3600 seconds = 2790 seconds.
So, it would take approximately 2790 seconds to go from 40 mph to 9 mph in 519 ft.