Question

A student performed the following steps to find the solution to the equation 2x2−147+15=02x2−147+15=0. Where did the student go wrong?

Step 1. Factor the polynomial into (x+5) and (x+9)
Step 2. x=550012−9=0
Step 3. x=−5 or x=9

A. in Step 1
B. in Step 2
C. The student did not make any mistakes; the solution is correct
D. in Step 3

Answer 1

The student went wrong in Step 2 by dividing incorrectly. The correct solutions to the equation can be found using the quadratic formula.

Step-by-step explanation:

The student went wrong in Step 2. Let's evaluate the steps:

1. The student correctly factored the polynomial into (x+5) and (x+9).
2. However, in Step 2, the student made an error when solving for x. Instead of dividing both sides of the equation by 2, the student mistakenly divided by 550012-9.
3. As a result, in Step 3, the student found the incorrect values of x=-5 and x=9.

To solve the equation 2x²-147+15=0 correctly, the student should have divided both sides by 2, which would give x² - 76x + 8 = 0. Then, the student could have used the quadratic formula to find the correct solutions.