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Evaluate ∑n=1[infinity]400+200+100+… and select the correct answer below.

A. Diverges
B. 700
C. 800
D. 1200

1 Answer

6 votes

Final answer:

The sum of the geometric series 400+200+100+... converges to 800 using the formula for the sum of an infinite geometric series, where the first term is 400 and the common ratio is 1/2.

Step-by-step explanation:

The series provided in the question is a geometric series whose first term is 400 and the common ratio is \(\frac{1}{2}\). The formula we use to evaluate the sum of an infinite geometric series is \(S = \frac{a}{1 - r}\), where \(S\) is the sum of the series, \(a\) is the first term, and \(r\) is the common ratio. In this case, we have \(a = 400\) and \(r = \frac{1}{2}\).

The sum of the series can be calculated as follows:
\[S = \frac{a}{1 - r} = \frac{400}{1 - \frac{1}{2}} = \frac{400}{\frac{1}{2}} = 400 \times 2 = 800\]

Therefore, the sum of the series \(400+200+100+\dots\) converges to 800, and the correct answer is C. 800.

User AndreasN
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