Question

P(x). Q(x) = R(x); if P(x) = x + 2 and R(x) = x³ – 3x2 - 6x – 2, what is Q(x)?

A. x² - 4x -²
B. x² + 4x - 2
C. x² + 4x + 2
D. x² - 5x + 4;R-2

Answer 1

To find Q(x), we need to solve the equation P(x) * Q(x) = R(x), where P(x) = x + 2 and R(x) = x³ – 3x² - 6x – 2. By substituting the values of P(x) and R(x) into the equation and simplifying, we find that Q(x) is equal to (x³ – 3x² - 6x – 2) / (x + 2).

Step-by-step explanation:

To find Q(x), we need to solve the equation P(x) * Q(x) = R(x), where P(x) = x + 2 and R(x) = x³ – 3x² - 6x – 2. We can start by substituting the values of P(x) and R(x) into the equation:

(x + 2) * Q(x) = x³ – 3x² - 6x – 2

To find Q(x), we need to solve for it. We can do this by dividing both sides of the equation by (x + 2):

Q(x) = (x³ – 3x² - 6x – 2) / (x + 2)

So, the value of Q(x) is given by the expression (x³ – 3x² - 6x – 2) / (x + 2).