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What is the mass of pure sulfuric acid (H₂SO₄) required to make a 20% solution of 150g of H₂SO₄?

a) 50g
b) 60g
c) 70g
d) 80g

1 Answer

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Final answer:

To make a 20% solution of 150g of H₂SO₄, the mass of pure sulfuric acid required is 30g.

Step-by-step explanation:

To find the mass of pure sulfuric acid required to make a 20% solution of 150g of H₂SO₄, we can use the concept of mass percentage. A 20% solution means that 20g of H₂SO₄ is dissolved in 100g of solution. So, if we want to find the mass of pure H₂SO₄ required, we need to set up a proportion:

20g H₂SO₄ / 100g solution = x g H₂SO₄ / 150g solution

Cross multiplying, we get:

20g H₂SO₄ * 150g solution = 100g solution * x g H₂SO₄

Dividing both sides by 100g solution, we get:

x g H₂SO₄ = 20g H₂SO₄ * 150g solution / 100g solution

Simplifying, we find that x = 30g. Therefore, the mass of pure sulfuric acid required is 30g.

User Afeez Aziz
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