The principal sum is approximately ₹2,796,610.17, and the rate of interest is approximately 4.72%. These values satisfy the given conditions of simple interest over 3 and 8 years.
To find the principal sum and the rate of interest, we can use the formula for simple interest:
![\[ A = P \left(1 + (rt)/(100)\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/wo9j79zpoy2s1fva08l7tgqo4957670gx7.png)
Where:
- A is the amount after t years,
- P is the principal sum (initial amount),
- r is the rate of interest, and
- t is the time in years.
Given that A = ₹27960 after 3 years and A = ₹34560 after 8 years, we can set up two equations:
For 3 years:
![\[ 27960 = P \left(1 + (3r)/(100)\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/igd1afik8edn2tg38gzux94348rwtedadd.png)
For 8 years:
![\[ 34560 = P \left(1 + (8r)/(100)\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/o24vyoelth1c7vwv0ksy7p335aa06663a4.png)
Now, you can solve these two equations simultaneously to find P and r. Subtract the first equation from the second to eliminate P:
![\[ 34560 - 27960 = P\left((8r)/(100) - (3r)/(100)\right) \]\[ 6600 = P \left((5r)/(100)\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/13knqql437fhetwi8vru8j8cw2vudywnmg.png)
Now, solve for P:
![\[ P = (6600)/((5r)/(100)) \]\[ P = (6600 * 100)/(5r) \]\[ P = (660000)/(5r) \]\[ P = 132000 / r \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/25we1rwl1ljdl4veglbi35asx8p0rpa1h6.png)
Now, substitute the value of P back into either of the original equations to solve for r. Once you find r, you can find P using the equation

Now, substitute this expression into one of the original equations, for example, the equation for 3 years:
![\[ 27960 = (132000)/(r) \left(1 + (3r)/(100)\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/xpm2wbs3m49f5wxscdswih29o0viheof3u.png)
Now, solve for r:
![\[ 27960 = (132000)/(r) + (3960)/(100) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/rdleauyat3pa9ywc52m02rrm4mhak44wdy.png)
Combine the fractions:
![\[ 27960 = (132000)/(r) + 39.6 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/a36ietfpnw8ei1mpce8e6bw561m9dgzrl5.png)
To simplify, let's multiply through by r to clear the fraction:
![\[ 27960r = 132000 + 39.6r \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/yp8292wis3atwmvxwum888u6gm0aovv9fn.png)
Subtract 39.6r from both sides:
![\[ 27960r - 39.6r = 132000 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/8w08q5o5e0wj7nlgjsqj7q0b66u78wbdrv.png)
Combine like terms:
![\[ 27920.4r = 132000 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/hvl67wzyz439ycp46932yhgzblifmjo4q5.png)
Now, solve for r:
![\[ r = (132000)/(27920.4) \]\[ r \approx 4.72\% \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ba7z6lwz16rbhsztmpzklq9ygyfkb8rgvm.png)
Now that we have the rate of interest r, you can substitute it back into the expression for P to find the principal amount P:
![\[ P = (132000)/(4.72\%) \]\[ P \approx 2,796,610.17 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/b45vsqbpxuq2maaoj6zg05fh1jkg7vlgr9.png)
Therefore, the principal sum is approximately ₹2,796,610.17 and the rate of interest is approximately 4.72%.