Question

By drawing the appropriate structure and writing the mechanism predict the products of the following reactions:

a) (CH₃)₂CHCH=CH₂ + Cl₂ + H₂O
b) (CH₃)₂CHCH=CH₂ + Cl₂ + H₂O
c) (CH₃)₂CHCH=CH₂ + Cl₂ + H₂O
d) (CH₃)₂CHCH=CH₂ + Cl₂ + H₂O

Answer 1

The products of the given reactions are ClCH₂CHCHCH₂OH.

Step-by-step explanation:

For reaction a), the appropriate structure is (CH₃)₂CHCH=CH₂. The mechanism for this reaction involves the following steps:

1. CH₃CHCHCH₂ + 2H₂ → CH₃CHCHCH₃ (Addition of H-atoms to the double bond)
2. CH₃CHCHCH₃ + Cl₂ → ClCH₂CHCHCH₃ (Substitution of one H-atom with Cl-atom)
3. ClCH₂CHCHCH₃ + H₂O → ClCH₂CHCHCH₂OH + HCl (Substitution of another H-atom with OH-group)

For reactions b), c), and d), the same mechanism is followed, with the only difference being the starting alkene molecule. The final products for b), c), and d) would be ClCH₂CHCHCH₂OH, ClCH₂CHCHCH₂OH, and ClCH₂CHCHCH₂OH respectively.