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He sells all the jacket potatoes, 2/3 of the sandwiches, and 3/4 of the baguettes at full price. He then reduces the prices of the remaining sandwiches and baguettes by half. What is the total cost of the sales that day? £

a) £0
b) £(Potatoes + (1/3)Sandwiches + (1/4)Baguettes)
c) £(Potatoes + (2/3)Sandwiches + (3/8)Baguettes)
d) £(Potatoes + (1/3)Sandwiches + (1/8)Baguettes)

User Linor
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1 Answer

4 votes

Final answer:

The total cost of sales includes all jacket potatoes, 2/3 of sandwiches, and 3/4 of baguettes sold at full price, and the remaining sandwiches and baguettes sold at half price. The formula to calculate the total cost of sales is £(Potatoes + (2/3)Sandwiches + (3/8)Baguettes), which corresponds to option c).

Step-by-step explanation:

The question pertains to calculating the total cost of sales based on the quantities sold at full price and the quantities sold at reduced price. To answer this question, we analyze the given percentages of products sold at full price and calculate the remaining quantities that will be sold at half price. We are given that all jacket potatoes are sold at full price, 2/3 of the sandwiches are sold at full price, and 3/4 of the baguettes are sold at full price. This means that 1/3 of the sandwiches and 1/4 of the baguettes are sold at half price. Therefore, if we denote the full price values of potatoes, sandwiches, and baguettes as Potatoes, Sandwiches, and Baguettes respectively, the total cost of the sales that day would be expressed as the sum of:

  • Full price sales of jacket potatoes: Potatoes
  • Full price sales of 2/3 of the sandwiches: (2/3)Sandwiches
  • Full price sales of 3/4 of the baguettes: (3/4)Baguettes
  • Half price sales of the remaining 1/3 of the sandwiches: (1/3)(1/2)Sandwiches = (1/6)Sandwiches
  • Half price sales of the remaining 1/4 of the baguettes: (1/4)(1/2)Baguettes = (1/8)Baguettes

Adding all these values together, we get the formula for the total cost of sales:

£(Potatoes + (2/3)Sandwiches + (3/4)Baguettes + (1/6)Sandwiches + (1/8)Baguettes)

Simplifying, we combine the terms for sandwiches and baguettes:

£(Potatoes + (2/3 + 1/6)Sandwiches + (3/4 + 1/8)Baguettes)

Which simplifies to:

£(Potatoes + (3/4)Sandwiches + (7/8)Baguettes)

Finally, this results in option c) £(Potatoes + (2/3)Sandwiches + (3/8)Baguettes) after considering that half of the 1/3 of sandwiches and 1/4 of baguettes sold at reduced price effectively contributes to (1/6) and (1/8) of their respective full prices.

User KitsuneYMG
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