Question

Liquid hydrogen peroxide, an oxidizing agent in many rocket fuel mixtures, releases oxygen gas on decomposition: 2 H₂O₂ (l) >>> 2 H₂O (l) + O₂ (g). The reaction releases 196.1 kJ. Calculate the decomposition of 484 kg of H₂O₂.

a) 234,400 kJ
b) 117,200 kJ
c) 468,800 kJ
d) 93,760 kJ

Answer 1

The decomposition of 484 kg of hydrogen peroxide releases approximately 1,403,622.45 kJ of heat.

Step-by-step explanation:

The decomposition of hydrogen peroxide, H₂O₂, can be represented by the equation 2 H₂O₂(l) >>> 2 H₂O(l) + O₂(g). In this reaction, 196.1 kJ of heat is released. To calculate the decomposition of 484 kg of H₂O₂, we need to convert the mass to moles. The molar mass of H₂O₂ is 34.02 g/mol, so the number of moles of H₂O₂ is 484,000 g / 34.02 g/mol = 14,245 mol. Since the reaction releases 196.1 kJ per 2 moles of H₂O₂, we can multiply the number of moles of H₂O₂ by the ratio 196.1 kJ / 2 mol to find the amount of heat released: 14,245 mol * (196.1 kJ / 2 mol) = 1,403,622.45 kJ. Therefore, the decomposition of 484 kg of H₂O₂ releases approximately 1,403,622.45 kJ of heat.