Final answer:
445 grams of water are needed to prepare a saturated solution containing 205 g of sodium chloride.
Step-by-step explanation:
To find the grams of water needed to prepare a saturated solution containing 205 g of sodium chloride, we need to compare the solubility of sodium chloride in water. The solubility of sodium chloride is given as 46.0 g in 100 g of water at 20°C. We can set up a proportion to solve for the grams of water:
(46.0 g / 100 g) = (205 g / x g)
Cross-multiplying and solving for x, we get x = 445 g. Therefore, 445 grams of water are needed to prepare the saturated solution containing 205 g of sodium chloride.