Question

A girl throws a ball up into the air. The ball starts with a speed of 10 m/s. What is the maximum height that the ball reaches assuming there is no air resistance? Gravity - 9.8 m/s².

A) 5 m
B) 10 m
C) 15 m
D) 20 m

Answer 1

The maximum height reached by the ball when thrown upwards with an initial speed of 10 m/s is calculated using the kinematic equation for uniformly accelerated motion, resulting in a height of approximately 5.1 meters.

Step-by-step explanation:

To find out the maximum height that the ball reaches when a girl throws it up into the air with an initial speed of 10 m/s, we need to use the kinematic equation for uniformly accelerated motion:

h = (v^2 - u^2) / (2 * g)

Here, h is the maximum height, v is the final velocity (0 m/s at the maximum height), u is the initial velocity (10 m/s), and g is the acceleration due to gravity (9.8 m/s²).

Plugging the values into the equation:

h = (0 - 10²) / (2 * 9.8)

h = (-100) / (19.6)

h = 5.1 m

Thus, the maximum height the ball reaches is approximately 5.1 meters, which is closest to option A) 5 m.