Answer:
The slope of the line
![m = -(1)/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/y44sp7v9qwm0lmxl7rdq5e6vv4w4e4ui2p.png)
The point ( x₁ ,y₁) = ( 2,1)
Explanation:
Explanation:-
Given that the line
![y -1 = -(1)/(2) ( x-2)](https://img.qammunity.org/2022/formulas/mathematics/college/qwvr7tptezwbv4x8bbrqy96jd4wigfggsu.png)
Comparing y- y₁ = m(x-x₁)
The slope of the line
![m = -(1)/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/y44sp7v9qwm0lmxl7rdq5e6vv4w4e4ui2p.png)
The point ( x₁ ,y₁) = ( 2,1)
The equation of the straight line
![y -1 = -(1)/(2) ( x-2)](https://img.qammunity.org/2022/formulas/mathematics/college/qwvr7tptezwbv4x8bbrqy96jd4wigfggsu.png)
2(y-1) = -(x-2)
2y -2 = -x +2
x + 2y -2-2=0
x +2y -4=0
Final answer:-
The equation of the straight line x+ 2y-4=0
The slope of the line
![m = -(1)/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/y44sp7v9qwm0lmxl7rdq5e6vv4w4e4ui2p.png)
The point ( x₁ ,y₁) = ( 2,1)