Final answer:
The mass of ice that would melt when 2 kg of copper is quickly transferred from boiling water at 100°C to a block of ice at 0°C without heat loss is 33/8 kg.
Step-by-step explanation:
To calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water at 100°C to a block of ice at 0°C without heat loss, we need to consider the heat transfer and the latent heat of fusion of ice. The heat transfer necessary to melt the ice can be calculated using the equation Q = mLf, where Q is the heat transfer, m is the mass, and Lf is the latent heat of fusion of ice.
In this case, the heat transfer required to melt the ice is equal to the heat transfer gained by copper. The specific heat capacity of copper is given as 400 J/(kg·K). The latent heat of fusion of ice is given as 3.3 x 10^5 J/kg. By equating the heat transfer for copper and the heat transfer for ice, we can calculate the mass of ice melted.
So, the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water at 100°C to a block of ice at 0°C without heat loss is 33/8 kg.